2013 年 11 月 – zcw的博客

另外一种扁平化、反扁平化json结构的方法（尽量使用“[]”）

2013年11月13日由 zciii 发表

{a:{b:1}} <==> {a[“b”]:1} 参考上一篇所做：

JSON.unflatten = function(data) {
    "use strict";
    if (Object(data) !== data || Array.isArray(data))
        return data;
    var regex = /\.?([^.\[\]]+)|\[(\d+)\]|\[([^\d\W]\w*)\]/g,
        resultholder = {};
    for (var p in data) {
        var cur = resultholder,
            prop = "",
            m;
        while (m = regex.exec(p)) {
            cur = cur[prop] || (cur[prop] = (m[2] ? [] : {}));
            prop = m[2] || m[1] || m[3];
			prop = prop.replace(/^[\'\"]|[\'\"]$/g,'');
        }
        cur[prop] = data[p];
    }
    return resultholder[""];
};


JSON.flatten = function(data) {
    var result = {};
    function recurse (cur, prop) {
        if (Object(cur) !== cur) {
            result[prop] = cur;
        } else if (Array.isArray(cur)) {
             for(var i=0, l=cur.length; i<l; i++)
                 recurse(cur[i], prop + "[" + i + "]");
            if (l == 0)
                result[prop] = [];
        } else {
            var isEmpty = true;
            for (var p in cur) {
                isEmpty = false;
                recurse(cur[p], prop ? prop+'["'+p+'"]' : p);
            }
            if (isEmpty)
                result[prop] = {};
        }
    }
    recurse(data, "");
    return result;
}

JSON.unflatten = function(data) {

"use strict";

if (Object(data) !== data || Array.isArray(data))

return data;

var regex = /\.?([^.\[\]]+)|\[(\d+)\]|\[([^\d\W]\w*)\]/g,

resultholder = {};

for (var p in data) {

var cur = resultholder,

prop = "",

while (m = regex.exec(p)) {

cur = cur[prop] || (cur[prop] = (m[2] ? [] : {}));

prop = m[2] || m[1] || m[3];

prop = prop.replace(/^[\'\"]|[\'\"]$/g,'');

}

cur[prop] = data[p];

}

return resultholder[""];

};

JSON.flatten = function(data) {

var result = {};

function recurse (cur, prop) {

if (Object(cur) !== cur) {

result[prop] = cur;

} else if (Array.isArray(cur)) {

for(var i=0, l=cur.length; i<l; i++)

recurse(cur[i], prop + "[" + i + "]");

if (l == 0)

result[prop] = [];

} else {

var isEmpty = true;

for (var p in cur) {

isEmpty = false;

recurse(cur[p], prop ? prop+'["'+p+'"]' : p);

}

if (isEmpty)

result[prop] = {};

}

recurse(data, "");

return result;

}

快速扁平化、反扁平化json结构 | Fastest way to flatten / un-flatten nested JSON objects

2013年11月13日由 zciii 发表

Here’s my much shorter implementation:

JSON.unflatten = function(data) {
    "use strict";
    if (Object(data) !== data || Array.isArray(data))
        return data;
    var regex = /\.?([^.\[\]]+)|\[(\d+)\]/g,
        resultholder = {};
    for (var p in data) {
        var cur = resultholder,
            prop = "",
            m;
        while (m = regex.exec(p)) {
            cur = cur[prop] || (cur[prop] = (m[2] ? [] : {}));
            prop = m[2] || m[1];
        }
        cur[prop] = data[p];
    }
    return resultholder[""];
};

JSON.unflatten = function(data) {

"use strict";

if (Object(data) !== data || Array.isArray(data))

return data;

var regex = /\.?([^.\[\]]+)|\[(\d+)\]/g,

resultholder = {};

for (var p in data) {

var cur = resultholder,

prop = "",

while (m = regex.exec(p)) {

cur = cur[prop] || (cur[prop] = (m[2] ? [] : {}));

prop = m[2] || m[1];

}

cur[prop] = data[p];

}

return resultholder[""];

};

JSON.flatten hasn’t much changed (and I’m not sure whether yo 继续>

reduce python list of objects to dict object.id -> object

2013年11月13日由 zciii 发表

In Python 3.x:

object_dict = {x.id: x for x in object_list}

1	object_dict = {x.id: x for x in object_list}

In both Python 3.x and Python 2.4+:

object_dict = dict((x.id, x) for x in object_list)

1	object_dict = dict((x.id, x) for x in object_list)

(x.id, x) for x in object_list is 继续>

对于现代开发来说，JavaScript就是一种垃圾语言

2013年11月12日由 zciii 发表

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